Programming Languages Problem Code: PROGLANGSubmit

Read problem statements in Mandarin, Bengali, Russian, and Vietnamese as well.

Chef is a software developer, so he has to switch between different languages sometimes. Each programming language has some features, which are represented by integers here.

Currently, Chef has to use a language with two given features $A$ and $B$ . He has two options --- switching to a language with two features $A_{1}$ and $B_{1}$ , or to a language with two features $A_{2}$ and $B_{2}$ . All four features of these two languages are pairwise distinct.

Tell Chef whether he can use the first language, the second language or neither of these languages (if no single language has all the required features).

Input Format

The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.
The first and only line of each test case contains six space-separated integers $A, B, A_{1}, B_{1}, A_{2}, B_{2}$ .

Output Format

For each test case, print a single line containing the integer $1$ if Chef should switch to the first language, or $2$ if Chef should switch to the second language, or $0$ if Chef cannot switch to either language.

Constraints

$1 \leq T \leq 288$
$1 \leq A, B, A_{1}, B_{1}, A_{2}, B_{2} \leq 4$
$A, B$ are distinct
$A_{1}, B_{1}, A_{2}, B_{2}$ are pairwise distinct

Subtasks

Subtask #1 (100 points): original constraints

Sample Input 1

3
1 2 2 1 3 4
3 4 2 1 4 3
1 2 1 3 2 4

Sample Output 1

1
2
0

Explanation

Example case 1: The first language has the required features --- features $1$ and $2$ .

Example case 2: The second language has the required features --- features $3$ and $4$ .

Example case 3: Neither language has both features $1$ and $2$ .

Solution in C

#include <stdio.h>

int main(void) {
 int t;
 scanf("%d",&t);
 while(t--){
     int a[6];
     for(int i=0;i<=5;i++){
         scanf("%d",&a[i]);
     }
     if((a[0]==a[2]||a[0]==a[3])&&(a[1]==a[2]||a[1]==a[3]))
         printf("1\n");
     else if((a[0]==a[4]||a[0]==a[5])&&(a[1]==a[4]||a[1]==a[5]))
     printf("2\n");
     else
     printf("0\n");
 }
}


Solution in C++


#include <bits/stdc++.h> 

using namespace std; 

#define ll long long 

void solve(); 

int main() 

{

    ios_base::sync_with_stdio(false); 

    cin.tie(NULL); 

#ifndef ONLINE_JUDGE 

    freopen("input.txt", "r", stdin); 

    freopen("error.txt", "w", stderr); 

    freopen("output.txt", "w", stdout); 

#endif 

    int t=1; 

    /*is Single Test case?*/ 

    cin >> t; 

    // t=1;  

    //single test case  -= Delete if t testCases =- 

    while (t--) { 

        solve(); 

        cout << "\n"; 

}

    cerr << "time taken : " << (float)clock() / CLOCKS_PER_SEC << " secs" << endl; 

    int z; 

    cin>>z; 

    return 0; 

}

void solve() 

{

    int a,b,a1,b1,a2,b2; 

    cin>>a>>b>>a1>>b1>>a2>>b2; 

    if((a==a1 && b==b1) || (a==b1 && b==a1)) cout<<"1"; 

    else if((a==a2 && b==b2) || (a==b2 && b==a2)) cout<<"2"; 

    else cout<<"0"; 

}

using namespace std; 
#define ll long long 
void solve(); 
int main() 
{ 
    ios_base::sync_with_stdio(false); 
    cin.tie(NULL); 
   
#ifndef ONLINE_JUDGE 
    freopen("input.txt", "r", stdin); 
    freopen("error.txt", "w", stderr); 
    freopen("output.txt", "w", stdout); 
#endif 
   
    int t=1; 
    /*is Single Test case?*/ 
     
    cin >> t; 
     
    // t=1;  
     
    //single test case  -= Delete if t testCases =- 
     
    while (t--) { 
        solve(); 
        cout << "\n"; 
    } 
   
    cerr << "time taken : " << (float)clock() / CLOCKS_PER_SEC << " secs" << endl; 
    int z; 
    cin>>z; 
    return 0; 
} 
void solve() 
{ 
    int a,b,a1,b1,a2,b2; 
    cin>>a>>b>>a1>>b1>>a2>>b2; 
    if((a==a1 && b==b1) || (a==b1 && b==a1)) cout<<"1"; 
    else if((a==a2 && b==b2) || (a==b2 && b==a2)) cout<<"2"; 
    else cout<<"0"; 
}

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